Question

If in a triangle ABC, first angle is twice of the second angle and the third angle is thrice of the first one. Find the measure of each angle of the triangle.

Answer 1

Answer:

let the First angle be x.

then the second angle be 2x.

and the third angle be 3x.

A/Q, x+2x+3x = 180°

= 6x =180°

=x=180°/6

= x =30°

first angle = 30°

second angle = 2x= 60°

third angle = 3x= 90°

Answer 2

Answer:

We know that in a △, the sum of all the interior angles is 180 ∘

⇒∠A+∠B+∠C=180 ∘

∠A=

2

∠B

2

∠B

+∠B+3∠B=180 ∴∠B=40 ∘

∠A=20 ∘

∠C=120 ∘