if in a triangle abc right angled at c tan b = 12by 5.find sin b
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In a right angled triangle ABC, right angled at C, tanB = 2sinB , then sin A+sinB is equal to
A
23+1
B
3
C
21
D
1
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Correct option is
A
23+1
⇒Given:tanB=2sinB
⇒cosBsinB=2sinB
⇒cosB=21
⇒B=600
Therefore A=900−600=300
⇒sinA+sinB
=sin300+sin600
=21+
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