Question

If in a triangle abc the altitude from what is the abc on opposite sides are in hp then sin a sin b sin c are in

Answer 1

hope you understand

Answer 2

$∆= \frac{1}{2}P 1a = \frac{1}{2} P2b = \frac{1}{2} P3c$

P1,P2,P3 are in H.P.

$⇒ \frac{2∆}{a} , \frac{2∆}{b}, \frac{2∆}{c}$are in H.P.

$⇒ \frac{1}{a} , \frac{1}{b} , \frac{1}{c}$are in H.P.

⇒a,b,c are in A.P

⇒sinA,sinB,sinC are in A.P