Question

If log5 (x2 + x) - log 5 (x + 1) = 2, then the value of x is

Answer 1

Hope this solution will help you

Answer 2

Answer:

The value of x would be 25.

Step-by-step explanation:

Given,

$log_5(x^2 + x) - log_5 (x+1) = 2$

$log_5(\frac{x^2+x}{x+1})=2$   $(\because log a - log b = log(\frac{a}{b}))$

$log_5(\frac{x(x+1)}{x+1})=2$

$log_5x = 2$

$\implies x = 5^2=25$  $(log_a x = b\implies x = a^b)$

Hence, the value of x would be 25.