If in a triangle angle B=90 sinC=4/5 then find the value of tanA
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sin c =4/5
angle b = 90
AB= 4 units
AC = 5 units
BC = 3 units
tan a = BC / BA
= 3/ 4
angle b = 90
AB= 4 units
AC = 5 units
BC = 3 units
tan a = BC / BA
= 3/ 4
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