If in a triangle,angles 2A=3B=6C then find B.
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2A=3B
or, A/B=3/2
or, A:B=3:2
Similarly,
3B=6C
or, B/C=6/3=2/1
or, B:C=2:1
Therefore,
A:B:C=3:2:1
Since the sum of angles in a triangle is equal to 180 degrees.
Angle A = (3/(3+2+1))x180) = (3/6)x180= 90 degrees
Angle B = (2/(3+2+1))x180) = (2/6)x180= 60 degrees
Angle A = (1/(3+2+1))x180) = (1/6)x180= 30 degrees
or, A/B=3/2
or, A:B=3:2
Similarly,
3B=6C
or, B/C=6/3=2/1
or, B:C=2:1
Therefore,
A:B:C=3:2:1
Since the sum of angles in a triangle is equal to 180 degrees.
Angle A = (3/(3+2+1))x180) = (3/6)x180= 90 degrees
Angle B = (2/(3+2+1))x180) = (2/6)x180= 60 degrees
Angle A = (1/(3+2+1))x180) = (1/6)x180= 30 degrees
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