Math, asked by Gurllsantiksan, 1 year ago

If in ∆ABC, AD is median and AM perpendicular to BC. THEN prove that AC2=AD2+BC×DM+1/4BC2

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Answered by Opal

3

Use readymade result of Pythagoras theorm in ▲ACD sice it is obtuse triangle
and the simplify what you get

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