Question

If in an A.P.,d=10 then find t6-t2​

Answer 1

I hope this helps you.

Answer 2

Answer:

t6-r2=60

Step-by-step explanation:

d=10

We know that

tn=a+(n-1)d.............(1)

Put n=6 in eq 1

t6=a+(6-1)10

t6=a+(5)10

t6=a+50...............(2)

Now; put n=2 in eq 1

t2=a+(2-1)10

t2=a+1*10

t2=a+10..............(2)

Now

t6-t2=a+50-a+10...........trom (2) &(3)

= 50+10. (+a-a=0)

t6-t2=60