If in an AP ,the 24th term of an AP is twice the 10th term,prove that 36th term is twice the 16th
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given =
a24 = 2 * a10
a + 23d = 2 * ( a + 9d )
a + 23d = 2a + 18d
5d = a ............. (1)
5d - a = 0
a36 = a + 35d
substituting (1)
a36 = 5d + 35d = 40d .......... (2)
2* a16 = 2 ( a + 15d )
substituting (1)
2 * a16 = 2 ( 5d + 15d )
2* a16 = 2 * 20d
2 * a16 = 40d.......... (3)
from (2) and (3)
a36 = 2*
a16 = 40d
thank you ☺
♪\(*^▽^*)/\(*^▽^*)/
given =
a24 = 2 * a10
a + 23d = 2 * ( a + 9d )
a + 23d = 2a + 18d
5d = a ............. (1)
5d - a = 0
a36 = a + 35d
substituting (1)
a36 = 5d + 35d = 40d .......... (2)
2* a16 = 2 ( a + 15d )
substituting (1)
2 * a16 = 2 ( 5d + 15d )
2* a16 = 2 * 20d
2 * a16 = 40d.......... (3)
from (2) and (3)
a36 = 2*
a16 = 40d
thank you ☺
NidhraNair:
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Answered by
0
Answer:
Answer Expert Verified
Therefore, according to the question. a36 = 40d and a16 = 20d, It is proved from above that the 36th term is twice the 16th term of the given AP.
Explanation:
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