Question

If in an isosceles triangle, each of the base angles is 40 degrees, then the triangle is

Answer 1

Answer:

$each \: base \: angle \: = \: 40°</p><p></p><p>,let \: the \: vertex \: = \: x \:</p><p></p><p>angle \: sum \: property \: = \: 180°</p><p></p><p>ATQ</p><p></p><p>x \: + \: 40° \: + \: 40° \: = \: 180° </p><p></p><p>x \: + \: 80° \: = \: 180°</p><p></p><p>x \: = \: 180° \: - \: 80° </p><p></p><p>x \: = \: 100° </p><p></p><p>Therefore \: vertex \: = \: 100°$

Answer 2

Answer:

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Step-by-step explanation: