if in C mass of proton is halfed , mass of neutron is tripled and mass of electron is doubled than calculate •/• change in mass.
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a element have,
electron=6
proton= 6
neutron=6
initial mass - mass of Neutron+ mass of proton
==> 6+6
==> 12 amu.
final mass = mass of Neutron + mass of proton
==> 3×6+6/2
==> 18+3
==> 21amu.
we know that,
•/• change in mass =
(final mass -initial mass) ×100
(initial mass)
==> (21 -12) × 100
12
==> 9 ×100
12
==> 75•/•
75•/• Ans.
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vreddyv2003:
comment done
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