Question

if in the circuit,
power dissipation is 150 w then R is​

Answer 1

Answer:

As we learnt in

if R=r -

P_{max}=\frac{E^{2}}{4r}

- wherein

Power delivered will be maximum

and

Parallel Grouping -

Potential - Same

Current - Different

- wherein

The equivalent resistance is Re_{2}= \frac{2\times R}{2+R}

Power dissipation P= \frac{v^{2}}{R}

150 = \frac{15\times 15}{Re_{2}}

= Re_{2} = \frac{15}{10}= \frac{3}{2}

\frac{2R}{2+R} = \frac{3}{2}

\Rightarrow 4R = 6+3R

R = 6\Omega

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