Question

If in the dimer of Be(OME)2
x = number of 2c-2e- bonds
y = number of 3c-2e bonds
z = number of 3c-4e bonds

Then find out the value of
(x + y)/z
​

Answer 1

Answer:

Total 2c−2e and 3c−2e bonds in Be(BeH

4

)

2

are 4,4 respectively.

As can be seen in the following structure, there are four bridges that corresponds to 3c−2e bonds. Remaining 4 bonds are 2c−2e bonds.

Answer 2

Total 2c−2e and 3c−2e bonds in $Be(OMe)_{2}$ ​are 4,4 respectively.

As can be seen in the following structure, there are four bridges that corresponds to 3c−2e bonds. Remaining 4 bonds are 2c−2e bonds.

and 3c-4e bonds are 1

now, $\frac{x+y}{z}$= $\frac{4+4}{1}$

                $=8$