Question

If in the triangle ABC, AB :BC:CA = 3:4:5 then find the values of the following:
(a) sin A
(b) cos A
(c) tan C + sec C​

Answer 1

Answer:

sin A = BC/AC = 4/5

cos A = 3/5

tan C = AB/BC = 3/4 & sec C = AC/BC = 5/4

tan C + sec C = 3/4 + 5/4 = 8/4 = 2

Answer 2

this is your answer....

hope so it helps you....

happy to help...