If in triangle ABC B = 90 AB = 12cm BC = 5cm then value of cot c is
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AB=12cm
BC=5cm
by hypotenuse formula, Ac=13cm
cot c=Bc/AB=5/12
BC=5cm
by hypotenuse formula, Ac=13cm
cot c=Bc/AB=5/12
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Hence, the value of cot C is 5/12.
Given:
△ABC where ∠B = 90°
AB = 12 cm
BC = 5 cm
To Find:
The value of cot C.
Solution:
We have been given a right-angled triangle △ABC where ∠B = 90°.
Hence, AC is the hypotenuse, and AB and BC are the other two sides of △ABC.
Now in any right-angled triangle, the cotangent of an angle is the ratio of the lengths of the adjacent side to the length of the side opposite to the given angle.
In △ABC,
The side adjacent to ∠C = BC = 5 cm
The side opposite to ∠C = AB = 12 cm.
Hence
cot C = (adjacent side) / (opposite side) = BC/AB = 5/12.
Hence, the value of cot C is 5/12.
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