If in triangle ABC,RS// BC, if AR=x-2 , RB=4x ,AS=x+6 and SC=12x ,then x=
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Step-by-step explanation:
(1) For Fig.a,
AB∥CD [ Given ]
∴ Quadrilateral ABCD is a trapezium.
∴
CO
AO
=
DO
BO
[ Diagonals of trapezium divides each other proportionally ]
⇒
4x−2
4
=
2x+4
x+1
⇒ 4(2x+4)=(x+1)(4x−2)
⇒ 8x+16=4x
2
−2x+4x−2
⇒ 4x
2
−6x−18=0
⇒ 2x
2
−3x−9=0
⇒ (x−3)(2x+3)=0
∴ x=3 or x=
2
−3
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