Question

If in two Triangles the sides of a triangle are proportional to the corresponding sides of the Other triangle then the corresponding angles are equal and hence the Triangles are similar...

Answer 1

Hello Friend....

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The answer of u r question is.....

Ans:

given,

triangle ABc and triangle DEF are such that

AB/DE = BC/EF = CA/FD (1)

RTP: <À=<D,<B=<E,<C=<F.....

PROOF:

DP/PE= DQ/QF AND PQ ll EF (CONVERSEOF BBT)


SO,
<P = <E AND <Q=<F

DP/DE = DQ/DF = PQ/EF


SO

BC=PQ

TRIANGLE ABC IS CONGRUENT TO TRIANGLE DPQ...

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Answer 2

Note : if two angles of triangle are equal to two angles of another triangle, then the two triangles are similar,

Here,

Given that corresponding angles are equal, so the given triangles are similar.





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