Question

If ina triangle AB =15 cm BC = 14CM and Ac =13 cm .find the area of triangle ABC
and hence it's altitude on BC

Answer 1

$perimeter = 15 + 14 + 13$
$p =4 2$
$s = p \: by \: 2$
$s = 42 \: by2$
$s = 21cm$
$\sqrt{s(s - a)(s - b)(s - c)}$
$\sqrt{21 \times 6 \times 7 \times 8}$
$\sqrt{7 \times 3 \times 3 \times 2 \times \times7 \times 2 \times 2 \times 2}$
$84 {cm}^{2}$

$1 \: by \: 2 \times 14 \times h = 84$

$h = (84 \times 2) \: by \: 14$
$h = 12 \: cm$

Answer 2

Answer:

Step-by-step explanation: