If income of X is 60% more than y and income of y is 40% more than z.find the income of X is how much percent more than z
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I think 124%.... I'm doubtful a little bit. If it is right than thank me and pls select it as a brainliest answer....Both methods are correct. Choose the one u like.....
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Income of X is 66.4% more than z
Step-by-step explanation:
Let the income of z be z
We are given that income of y is 40% more than z
Income of y = z+0.04z=1.04z
Income of X is 60% more than y
Income of X = 1.04z+0.6(1.04z)=1.664 z
Difference between income x and z = 1.664z-z=0.664z
Income of x is more than z =
Hence Income of X is 66.4% more than z
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52.
X's income is 20% more than Y's income. Y's income is less than X's income by
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