Question

If initial concentration is reduced to 1/4 in a zero order reaction the time taken for half the reaction to complete

Answer 1

use the formula as shown in the picture
hope you get the answer and my answer is correct...
may it helps you!!

Answer 2

Answer: The time taken for half the reaction to complete when initial concentration is reduced to 1/4 will be:

$t_{\frac{1}{2}}=\frac{[A_O]}{8k}$

Explanation:

In, zero order reaction the time taken for half the reaction to complete:

$t_{\frac{1}{2}}=\frac{[A_O]}{2k}$

$t_{\frac{1}{2}}$ = Time taken for half the reaction to complete

$[A_O]$ = initial or starting concentration of a reactant

k = Rate constant of the reaction

When initial concentration is reduced to 1/4 then time taken for the reaction to complete:

$t_{\frac{1}{2}}=\frac{\frac{1}{4}[A_O]}{2k}=\frac{[A_O]}{8k}$