If ∆ is an operation such that for integers a and b we have
a∆ b = a × a + b × b – a × b, then find
(-4) ∆ 2.
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Answer:
from given information
a*b = a×b + (a×a + b×b)
so (-3)*(-5) = (-3)×(-5) + ((-3)×(-3) + (-5)×(-5))
= 15 + (9 +25)
= 15 + 34
(-3)*(-5) = 49
(-6)*2 = (-6)×2 + ((-6)×(-6) + 2×2)
= (-12) + (36 + 4)
= -12 + 40
(-6)*2 = 28
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