Question

If θ is angle that vector →A=2^i+3^j+5^k makes with x-z plane then​

Answer 1

Answer:

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Answer 2

Explanation:

ANSWER

Unit vector along X axis =i^

Unit vector along Y axis =j^

Unit vector along Z axis =k^

We use dot product to find angle 

a.b=abcosθ

Now with X axis:

A.i^=A×1×cosθ

(5i^+0j^+5k^).i^=52cosθ

5=52cos∴cosθ=21 

θ=4π

Now with Y axis:

A.j^=A×1×cosθ

(5i^+0j^+5k^).j^=52cosθ

0=52cosθ

∴cosθ=0 

θ=2