Question

If it cost 1600 rupees to fence a rectangular park of length 20 cm at the rate of 25 rupees per meter . find the breadth of the park and its perimeter. also find its area​

Answer 1

☞Question

If it cost 1600 rupees to fence a rectangular park of length 20 cm at the rate of 25 rupees per meter . find the breadth of the park and its perimeter. also find its area.

☞Solution.

Total cost = $\sf\green{1600}$

Rate of fence= $\sf\green{25}$

$\sf\red{Then\:area\:A\: rectangular\:}$

$\sf\red{total\:cost\:/rate\: of\: fance}$

                                               

↝ $\sf\green{1600/25}$

 ↝ $\sf\green{64m^2}$

☞Therefore, area = $\sf\green{64m^2}$

Length of the park = $\sf\red{20}$

Breadth = $\sf\green{?}$

Area of rectangle = $\sf\pink{l × b}$

                   

↝  $\sf\red{64}$ = $\sf\green{20× breadth}$

↝  $\sf\pink{64/20}$= $\sf\green{b}$

↝    $\sf\green{3.2}$  = $\sf\green{b}$

☞Therefore breadth is $\sf\green{3.2m}$

So perimeter of the rectangular park

  ↝    $\sf\red{2 ( l + b )}$                                                      

 ↝ $\sf\green{2( 20+3.2)}$

↝  $\sf\green{ 2 × 23.2 }$

↝  $\sf\green{ 46.4}$

☞So,

↝   $\sf\red{breadth = 3.2m}$

↝  $\sf\pink{ perimeter = 46.4m}$

↝  $\sf\green{ area = 64m^2 }$

$\pink{hope\: this\:helps\:you}$

Answer 2

Step-by-step explanation:

Given: Length = 500 m and breadth = 300 m, cost of 1m2 of land = Rs. 10,000

Area = Length

×

Breadth

=

500

×

300

=

150000

sq m

Price of Land = Area

×

cost per sq m

=

150000

×

10000

= Rs. 1,500,000,000