If it is given that
(a +b)²+ (b+c)² + (c+d) ² =
4 (ab + bc+cd)
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Answer:
Step-by-step explanation:
A2+b2+2ab+b2+c2+2bc+c2+d2+2cd= 4ab+4bc+4cd
A2+b2+b2+c2+c2+d2=2ab+2bc+2cd
A2+b2-2ab+b2+c2-2bc+c2+d2-2cd=0
(a-b)^2 + (b-c)^2+ (c-d)^2= 0
(a-b)^2 =0 ; (b-c)^2=0; (c-d)^2=0
a-b=0 ; b-c=0 ; c-d=0
a=b; b=c; c=d
a=b=c=d
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