Question

If k+1,3k and 4k+2 be any three consecutive terms of an AP , find the value of k. ??​

Answer 1

Since k+1, 3k and 4k+2 are in AP....

3k-k-1= 4k+2-3k

2k-1=k+2

k=3

HOPE IT HELPS YOU......❤️❤️❤️

Answer 2

Step-by-step explanation:

• first term (a) = k+1
• second term (b) = 3k
• third term (c) = 4k+2

$\boxed{\sf a+c=2b}$

$\longmapsto \sf k+1+4k+2=2(3k)$

$\longmapsto \sf 5k+3=6k$

$\longmapsto \sf 6k-5k=3$

$\longmapsto \sf k=3$