Question

If k-1,k+3 and 3k-1 are in an ap then find value of k

Answer 1

$k + 3 = \frac{k - 1 + 3k - 1}{2}$
$k + 3 =( 4k - 2) \div 2 \\ 2k + 6 = 4k - 2 \\ 2k = 8 \\ k = 4$
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