If k+1=sec square theta (1+sin theta) (1-sin theta) then find the value of k
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Answered by
244
Let theta be @
K+ 1 = sec square@ [ 1- sin@]{1 - sin@}
K+ 1 = sec square@ [1] - {sin square@}
K+1 = sec square @[ cos square @]
K +1= 1
K=0
Hope this will help you
Answered by
145
Answer: given that::: K + 1 = sec²ø (1+sinø) (1-sinø) therefore K is equals to zero 0 the solution is given below if you like it & you understand it mark me as a brainlist.....
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