Question

Two candles of equal length start burning at the same time One of the candle burns in 5h and the other candle in 4 h After how much time one candle will be 2 times the length of the other candle

Answer 1

Assuming both the candle burn uniformly. Let length of each candle be xx metre 

First candle can burn for 2424 hrs
=> Length of the first candle burned in 11 hr =x24=x24 metre 

Second candle can burn for 1616 hrs
=> Length of the second candle burned in 11 hr =x16=x16 metre 

Assume both the candles were burning for tt hours. Then
(x−tx24)=2(x−tx16)x−tx24=2x−tx8x=tx121=t12t=12 hours(x−tx24)=2(x−tx16)x−tx24=2x−tx8x=tx121=t12t=12 hours

i.e., each candle was burning for 1212 hours..........

Please mark it as brainiest answer .......