Question

If k + 1 = sec2 A (1 + sin A)(1
A (1 + sin A)(1 – sinA), then find the value of k​

Answer 1

Answer:

sec

2

θ(1+sinθ)(1−sinθ)=k+1

sec

2

θ(1−sin

2

θ)=k (a+b)(a−b)=a

2

−b

2

sec

2

θcos

2

θ=k

cos

2

θ

1

.cos

2

θ=k

k=1