if (k,-2) (0,1) (5,4)are collinear points then find k
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K is equal to 7..by using the formula of area of triangle
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using area of Δ =1/2(x1(y2-y3)+x2(y3-y1)+x3(y1-y2) ==>0
0 = 1/2(k(1-4)+0(4+2)+5(-2-1)
0 = -3k+0-15
k = -5
0 = 1/2(k(1-4)+0(4+2)+5(-2-1)
0 = -3k+0-15
k = -5
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