Question

If k+2,4k-6,3k-2,are the three consecutive terms of an ap then find the value of k

Answer 1

Since we know a+c=2b
K+2+3k-2=2(4k-6)
4k=8k-12
-4k=-12
K=3

Answer 2

Answer:

(k+2)+(3k−2)=2(4k−6)

⇒4k=8k−12

⇒4k−8k=−12

⇒−4k=−12

⇒4k=12

⇒k=

4

12

=3

Hence k=3.