Question

if K +2, 4K-6 and 3K-2 are the consecutive terms of an arithmetic progression, then K =?
Options
A) 3
B)0
C) 2
D) 1
Please give the answer with explaination
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Answer 1

Answer:

To be terms of an AP the difference between two consecutive terms must be the same

So if k+2, 4k-6 & 3k-2 are terms of an AP, then

4k-6–(k+2) = 3k-2–(4k-6)

4k-6-k-2=3k-2-4k+6

3k-8= –k+4

4k = 12

k =12/4=3

Thus the value of k is 3

Answer 2

Answer:

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