if k+2,4k-6 and 3k-2 are three terms of an ap then the value of k is
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6
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if k+2,4k-6,3k-2 are in ap
then 4k-6-(k+2)=3k-2-(4k-6)
4k-6-k-2=3k-2-4k+6
3k-8=-k+4
3k+k=4+8
4k=12
k=3
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3
Answer: given problem is given by two methods
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