Math, asked by radhikabansal2015, 8 months ago

if k+2,4k-6 and 3k-2 are three terms of an ap then the value of k is​

Answers

Answered by singhkhushmeet309
6

Answer:

if k+2,4k-6,3k-2 are in ap

then 4k-6-(k+2)=3k-2-(4k-6)

4k-6-k-2=3k-2-4k+6

3k-8=-k+4

3k+k=4+8

4k=12

k=3

Answered by tennetiraj86
3

Answer: given problem is given by two methods

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