Question

if k+2,4k-6 and 3k-2 are three terms of an ap then the value of k is​

Answer 1

Answer:

if k+2,4k-6,3k-2 are in ap

then 4k-6-(k+2)=3k-2-(4k-6)

4k-6-k-2=3k-2-4k+6

3k-8=-k+4

3k+k=4+8

4k=12

k=3

Answer 2

Answer: given problem is given by two methods