Question

If ( k-2) x2+2(k-12)x+2=0 then k=?​

Answer 1

(k-2)x^2+2(k-12)x+2=0

(kx^2-2x^2)+(2xk-24x)+2=0

kx^2-2x^2+2xk-24x+2=0

2xk(x-x+1-12k+xk)=0

2xk(1-12k+xk)=0

So,2xk=0

2k=0/x

2k=0

k=0/2

K = 0.

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