Question

If K, 2K-1, 6 are in AP, then find the value of K.

Answer 1

Hi friend!!

We know that if a,b,c are in A.P, then 2b=a+c

Given,

If K, 2K-1, 6 are in AP

→2(2k-1)=k+6

4k-2=k+6

3k=8

k=8/3

I hope this will help you ;)

Answer 2

We know, 2b = a + c

========================

Here,

2(2k - 1) = 6 + k

=> 4k - 2 = 6 + k

=> 4k - k = 6 + 2

=> 3k = 8

=> k = 8/3



I hope this will help you

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