Math, asked by rshalliyavar, 1 year ago

if K , 2K-1 AND 2K+1 ARE THREE CONSECUTIVE TERMS OF AN AP., WHAT IS THE VALUE OF K?

Answers

Answered by Anonymous
8


given,

k , 2k-1 and 2k+1 are in a.p

then,

2k-1-k =2k+1-(2k-1)

k-1      = 2k+1-2k+1

k-1      =2

k          =2+1

k          =3

therefore k value is 3

Answered by shruthi2000
3
In an A.P d=t2-t1 K,2k-1,2k+1(given) => 2k-1-k=2k+1-(2k-1) =>k-1=2k+1-2k+1 =>k-1=2 =>k=2+1 =>k=3 The value of k is 3
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