if K , 2K-1 AND 2K+1 ARE THREE CONSECUTIVE TERMS OF AN AP., WHAT IS THE VALUE OF K?
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Answered by
8
given,
k , 2k-1 and 2k+1 are in a.p
then,
2k-1-k =2k+1-(2k-1)
k-1 = 2k+1-2k+1
k-1 =2
k =2+1
k =3
therefore k value is 3
Answered by
3
In an A.P
d=t2-t1
K,2k-1,2k+1(given)
=> 2k-1-k=2k+1-(2k-1)
=>k-1=2k+1-2k+1
=>k-1=2
=>k=2+1
=>k=3
The value of k is 3
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