If k,(2k-1) and(2k+1)are three successive term of an ap find the value of k.
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d = a2-a1
d = a3-a2
equating both the equations we get
a2-a1 = a3-a2
2k-1-k = 2k+1-2k+1
k = 3
d = a3-a2
equating both the equations we get
a2-a1 = a3-a2
2k-1-k = 2k+1-2k+1
k = 3
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