Question

If (k - 3),(2k + 1) and (4k + 3) are the terms of G. P. , find the value of k.

Answer 1

since (k-3), (2k+1), (4k+3) are the terms of GP
therefore,
(2k+1)/(k-3)=(4k+3)/(2k+1)
(2k+1)^2=(4k+3)(k-3)
4k^2+4k+1=4k^2-12k+3k-9
4k+1=-9k-9
4k+9k=-9-1
13k=-10
k=-10/13