Question

If (k-3) , (2k+1) and (4k+3) are three consecutive terms of AP, find the value of k.​

Answer 1

Answer:

since (k-3),(2k+1) and (4k+3) are in A.P

so, 2×(2k+1)= k-3+ 4k+3

4k+2= 5k

k=2

Step-by-step explanation:

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