Question

If k+9,2k-1, and 2k+7 are in AP then find k.

Answer 1

Since, k+9,2k-1,2k+7 are in ap.....so there common difference must be same....

Therefore,

[2k-1] - [k+9] = [2k+7] - [2k-1]

after solving this we get,

k=4

Hope it helps you.....

Answer 2

k+9-2k-1=k+7+k+7

the answer is 4