Question

If K.E. of a body increases by 6%, then momentum
will increase by :-
(1) 1.5%
(2) 9%
(3) 3%
(4) 2%​

Answer 1

Explanation:

For original mass m and velocity v, kinetic energy

e = 1/2mv^2

Same mass but new velocity V, and kinetic energy

E is 6% more than e

E = 1.06e

1/2mV^2 = 1.06*1/2mv^2

Multiply by 2/m

V^2 = 1.06v^2

V = sqrt(1.06v^2) = sqrt(1.06)*v = 1.0296v

Momentum = mV = 1.0296mv

So momentum is now 2.96 = 3% greater.

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