Question

if k is greater than 0 and the product of roots of the equation x^2-3kx+2e^logk-1=0 is 7, then the sum of the roots=?

Answer 1

Answer:

Correct option is C)

Since the product of roots is 7

a

c

=7

By simplifying and taking natural log (log to the base e) on both sides

logk

2

=log4

Therefore

k

2

=4

k=±2

Since input value of log cannot be negative

k=2

Therefore sum of the roots

α+β=−(−3k)=3(2)=6

Step-by-step explanation:

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