If k,k2k-1 and 2k +1 are 3 consecutive terms of an ap then find k
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a1=k,a2=2k-1,a3=2k+1
:-a2-a1=a3-a2
2k-1-2=2k+1-(2k-1)
K-1=2k+1-2k+1
K=1+1+1
K=3
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