Question

If kcl crystallizes in fcc lattice then number of unit cells in its 0.2mol is

Answer 1

Answer:

Explanation:

no. of atoms in KCl =mole × Na( avogadro's no)

                                = 0.2 × 6.022 × 10^ 23

                                =1.20 × 10^23

now FCC lattice contains 4 atoms per unit cell

so for 1.20 × 10^ 23 it will be = 1.20 × 10^23/4

                                               = 3.01 × 10^22

I HOPE THIS IS HELPFUL

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