Question

If kf and kb represents the equilibrium constants of the forward and backward chemical reaction respectively of a particular reversible reaction then what i the relationship between kf and kb???

Answer 1

relation b/w kf and kB
KC= kf /kB
or kc×kB=Kf
kc here is the equilibrium constant

Answer 2

Answer:

The relationship between $K_f\& K_b$ is that product of equilibrium constants of the forward and backward chemical reaction is always 1.

Explanation:

$aA+bB+\rightharpoons cC+dD$

Equilibrium constant for forward reaction:

$K_f=\frac{[C]^c[D]^d}{[A]^a[B]^b}$...[1]

Equilibrium constant for backward reaction:

$K_b=\frac{[A]^a[B]^b}{[C]^c[D]^d}$

$\frac{1}{K_b}=\frac{[C]^c[D]^d}{[A]^a[B]^b}$...[2]

Using [2] in [1]

$K_f=\frac{1}{K_b}$

$K_f\times K_b=1$

The relationship between $K_f\& K_b$ is that product of equilibrium constants of the forward and backward chemical reaction is always 1.

$K_f\times K_b=1$