if kinetic energy is increased by 36% what is percentage change in momentum? with solution plz
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Therefore, momentum changes by 6%.
Hope it helps.....
Hope it helps.....
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Kinetic energy ∝ Momentum²
K ∝ p²
ΔK / K = 2 × Δp/p
36/100 = 2 × Δp / 100
Δp = 18%
Momentum is increased nearly by 18%
K ∝ p²
ΔK / K = 2 × Δp/p
36/100 = 2 × Δp / 100
Δp = 18%
Momentum is increased nearly by 18%
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