If kinetic energy of a proton is increased nine times the wavelength of the debroglie wave associated with it would become
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We know that debroglie wave length is given as
Lemda = h/√2KM
Here lemda is wavelength
h is Planck's constant
k is kinetic energy
M is mass of photon.
Acc. to ques.
K = 9K
Lemda' =1/3 Lemda
Hope you get your answer.
Lemda = h/√2KM
Here lemda is wavelength
h is Planck's constant
k is kinetic energy
M is mass of photon.
Acc. to ques.
K = 9K
Lemda' =1/3 Lemda
Hope you get your answer.
luckysr0599:
Explain it in steps
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