if l=0 electro s are present in which orbital
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Explanation:
The energy order of the respective orbital can be compared by their n+l values. In case of equal n+l values of orbital higher energy corresponds to the orbital whose n value is greater.
In (a), the electron is present in 4s-orbital ⇒n+l=4
In (b), the electron is present in 3p-orbital ⇒n+l=4
In (c), the electron is present in 3d-orbital ⇒n+l=5
In (d), the electron is present in 3s-orbital ⇒n+l=3
Therefore, the decreasing order of energies of orbitals is: 3d>4s>3p>3s.
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