Question

If l = {0^n1^n | n >=0}, then what length is to be taken to disprove that l is regular using pumping lemma

Answer 1

Answer:

Step-by-step explanation:

see attavhme ny 633203.1230

Answer 2

안녕하세요. 도움이 되었으면 좋겠습니다 ....

If A is a Regular Language, then there is a number p (the pumping length) where if s is any string in A of length at least p, then s may be divided into 3 pieces, s = xyz, satisfying the following conditions: a. For each i ≥ 0, xyiz ∈ A, b. |y| > 0, and c.