If l is the length of a diagonal of a cube of volume V, then
A. 3V=l³
B. V=l³
C. 3V=2 l³
D. 3V= l³
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Concept used :
Diagonal of a cube = √a² + a² + a² = √3a² = √3a
The line segment joining the opposite vertices is called a diagonal of a cube.
Mistake in the options :
A. 3V = l³
B. √3V = l³
C. 3√3V = 2 l³
D. 3√3V = l³
Given: l is the length of a diagonal of a cube of volume V.
Diagonal of a cube ,l = √3a
Edge of a cube , a = l/√3
Volume of cube , V = a³
V = (l/√3)³
V = l³/(3√3)
l³ = 3√3V
Option (D) l³ = 3√3V is correct.
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Answered by
1
Diagonal = √3a
Volume = a^3
Thus;
a = l/(√3)
a = ³√V
a = a
l/√3 = ³√V
Cubing on both sides:
l³ = 3√3 V
That's the solution.
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